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A construction for sets of integers with distinct subset sums
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由 T Bohman 著作1998被引用 37 次 — Abstract. A set S of positive integers has distinct subset sums if there are 2|S| 2 | S | distinct elements of the set {∑x∈Xx:X⊂S}.
a construction for sets of integers with distinct subset sums
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由 T Bohman 著作1998被引用 37 次 — This now stands as the best known upper bound on f(n). 1 Introduction. A set S of positive integers has distinct subset sums if the set. P.
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由 T Bohman 著作1998被引用 37 次 — Presentation Mode Open Print Download Current View. Go to First Page Go to Last Page. Rotate Clockwise Rotate Counterclockwise. Text Selection Tool
A construction for sets of integers with distinct subset sums.
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由 T Bohman 著作1998被引用 37 次 — A construction for sets of integers with distinct subset sums. Bohman, Tom · The Electronic Journal of Combinatorics [electronic only] (1998). Volume: 5, Issue ...
A Construction for Sets of Integers with Distinct Subset Sums
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F (n) is conjectured to be c2 c2 n for some constant c and a construction is given that yields f(n) that yields c(n). A set S of positive integers has ...
(PDF) Integer Sets with Distinct Subset-Sums
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2024年10月22日 — In Section 1 we introduce the problem of finding minimal-height sets of n natural numbers with distinct subset-sums (SSD), and in Section 2 ...
Set with distinct subset sums
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2014年12月16日 — The problem is as follows: Given a set A with distinct positive integer elements, prove that there always exists another set B consisting of positive integers.
1 個答案 · 最佳解答: The proof shall be by strong induction over the number of elements of A.
So we assume it has been proven for sets with n elements or less.
now notice ...
Sets of Integers Whose Subsets Have Distinct Sums
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由 RK Guy 著作1982被引用 42 次 — The subsets of the set of integers {2i: 0 ≤ i ≤ k) all have distinct sums. For a maximum number, m, of positive integers, the chapter discusses if it is ...
Algorithm for generating a set of Subset-Distinct-Sum ...
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2014年9月22日 — Method: · For N, find T = 2^P , where T is the highest power of two that is less than or equal to N. That is: P = Floor( Log2(N) ) , and; T = 2^P.
2 個答案 · 最佳解答: For any value of N, it is readily possible to generate up to Floor(Log2(N))-1 numbers (which ...
Sets with distinct subset sums
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由 P Erdos 著作 — Say that a set $ S \subseteq {\mathbb Z} $ has distinct subset sums if distinct subsets of $ S $ have distinct sums.