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Every lobster is odd-elegant
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由 X Zhou 著作2013被引用 38 次 — A graph G having q edges is odd-elegant if it admits a mapping f : V ( G ) → { 0 , 1 , 2 , … , 2 q − 1 } with f ( u ) ≠ f ( v ) for distinct u , v ∈ V ( G ) ...
Every lobster is odd-elegant
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由 X Zhou 著作2013被引用 38 次 — We show that every lobster is odd-elegant. Recommended articles. References (11). J.-G. Wang et al. The gracefulness of a class of lobster trees. Math. Comput ...
Every lobster is odd-elegant | Request PDF
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2024年10月22日 — 3) Lobster-neighbor-method: In [41] and [42] , the authors have proven: Each lobster admits one of odd-graceful labelling and odd-elegant ...
Every lobster is odd-elegant
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Semantic Scholar extracted view of "Every lobster is odd-elegant" by Xiangqian Zhou et al.
IPRL: Vol 113, No 1-2
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Every lobster is odd-elegant ... A graph G having q edges is odd-elegant if it admits a mapping f:V(G)->{0,1,2,...,2q-1} with f(u)<>f(v) for distinct u,v@__ __V(G) ...
Replying to @Jacob Knowles We got another one ...
TikTok · Jacob Knowles
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TikTok · Jacob Knowles
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Odd-graceful labeling algorithm and its implementation ...
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An algorithm and its implementation for odd-elegant labeling of general sun graph Sm,n [J] ... Every lobster is odd-elegant [J] . Information Processing Letters.
Connections between traditional coloring/labeliings and new set ...
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... such that the set of all edge labels is equal to {1,3,5,…,2q−1}{1,3,5,…,2q−1}. We show that every lobster is odd-elegant. View. Show abstract. Graph Theory.
Remember when Red Lobster was fancy? : r/GenX
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2024年5月20日 — Last week, the multinational conglomerate that owns the corpse of Red Lobster unexpectedly closed dozens of restaurants across the country ...
116 個答案 · 最佳解答: I was taken to Red Lobster for dinner on my very first date. My 16 year old self thought ...