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How To Fix Age of Wonders 4 Not Launching Error On PC | Fix Age of Wonders 4 Won't Launch Error https://lnkd.in/gDFUYZnB
How To Fix Age of Wonders 4 Not Launching Error On PC | Fix Age of Wonders 4 Won't Launch Error
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True authenticity is rare nowadays…
Investing millions in Main St businesses & teaching you how to own the rest | HoldCo, VC fund, Founder
Hot take: you can either be PC, or you can be authentic.
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Hi. Sometimes simple things need simple solutions.
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🔍 Exploring Extremum Points: A Math Adventure! I recently encountered an intriguing problem raised by Lee Chan Lye: https://lnkd.in/dZVShfmb Given x, y, z≥0, maximize the function f(x,y,z)= x^3*y + y^3*z + z^3*x subject to the constraint of x+y+z=3. Using partial derivatives, we found a minimum value of 3 (which is not too bad!). However, the maximum we obtained was less than the expected maximum value of 2187/256 which can be computed with x=9/4, y=3/4 and z=0. But here’s where it gets even more fascinating: when we initially set z=0 and simplify our expression to focus on f(x,y)= x^3*y while substituting y=3−x, we unearth that hidden treasure! 🎉 Using the technique of differentiation, we immediately arrive at the maximum value of 2187/256. This exploration reminds us that sometimes a different approach—like carefully choosing our variables—can lead to remarkable discoveries. 🍬 Math is not just about crunching numbers; it’s about delving into possibilities and enjoying the journey along the way. I would love to hear your thoughts and insights on this problem—what approaches or techniques do you find most effective in optimization? Happy calculating, everyone! #Mathematics #Optimization #Calculus #ProblemSolving #MathAdventure #Learning #Innovation #STEM
Give it a try and have fun! Will post my solution in a few days.
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Easy and quick fix😜
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(5,3), (2,6),(3,4) A different approach to solve this problem using inequality If a>b=> (1+1/a)(1+2/b)<(1+1/b)(1+2/b) =>2b^2<(b^2+3b+2) => b^2-3b-2<0 =>( 3-sqrt(13))/2 <b <(3+sqrt(13))/2 => 0<b<=3 (using b is positive integer) => b=1,2,3 Only for b=3 a=5, so one solution is (5,3) No a possible now if b>=a then replacing b with a in case a>b, we get possible value of a as 1,2 3 So only solution here is (2,6)(3,4)
Give it a try and have fun! Will post my solution in a few days.
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Figure out what you can control and what you can't. Then decide if what you can't is ok with you.
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Please subscribe to my channel! Thank you! 📌 Struggling with memory lapses and need a quick fix? Look no further! In this action-packed video, (Improve Your Memory FAST with the 80-20 Rule) we'll show you how to harness the power of the 80-20 rule (Pareto Principle) to elevate your memory game to new heights. Discover how this simple shift can transform your recall abilities instantly! #learning #learningjourney #learninghacks #memoryhacks #studyhacks #studytips #letsconnect #personaldevelopment https://lnkd.in/dhivQqV4
Improve Your Memory FAST with the 80-20 Rule!
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