💻 Day 40 of 100 Days of Code 💻 Today, I tackled LeetCode problem #476 - Number Complement. 🔄 ### Problem Overview: The challenge was to find the complement of a given positive integer, which involves flipping all bits in its binary representation. ### My Approach: - Bit Manipulation: I computed the bitwise complement by first determining the length of the binary representation and then flipping all bits up to that length. - Efficiency: The solution was efficiently executed using bitwise operations, which are fast and require minimal space. ### Complexity: - Time Complexity: O(1), since the operations are constant time regardless of the input size. - Space Complexity: O(1), as no extra space is required beyond a few variables. This problem was a great exercise in understanding binary representation and bitwise operations, which are crucial for low-level programming and optimization tasks. #100DaysOfCode #LeetCode #BitManipulation #ProblemSolving #CodingJourney
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Day 41 of #100DaysOfProgrammingChallenge Challenge completed: Solved LeetCode Problem #2044 - Count Number of Maximum Bitwise-OR Subsets Problem Breakdown: The task was to determine the maximum possible bitwise OR of a subset of integers from an array and count how many subsets achieve that maximum OR value. A subset can be derived by removing some or no elements from the array, and the subsets are considered different if they involve different indices. Example: Input: nums = [3, 1] Output: 2 Approach: First, calculate the maximum OR value that can be achieved by combining all elements in the array. Using recursion, explore all possible subsets of the array. Each time a subset reaches the maximum OR value, increase the count. Recursively building subsets ensures that we check every possible combination. This problem was an exciting way to dive into bitwise operations and subset generation, pushing for an efficient approach to explore all possibilities. I enjoyed tackling the recursion and bitwise logic! #CodingChallenge #ProblemSolving #Leetcode
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"Every line of code has a purpose—debugging and fine-tuning to ensure smooth execution and optimal performance." "Tracked down a pesky bug hiding in the logic! A few tweaks here and there, and now everything works smoothly." . . . . #ByteZenTechnologies #TechInnovation #SoftwareDevelopment #CodeOptimization #TechSolutions #Debugging
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🔗 Day 14 of My 60-Day Problem-Solving Challenge 🔗 Today’s challenge: "Longest Subarray With Maximum Bitwise AND." 🤖 Combining logic and bitwise operations for an interesting deep dive! #LeetCode #ProblemSolving #60DaysChallenge #CodingJourney #Day14 #BitwiseAND #Subarray
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#Day45 in Solving problem of the from LeetCode 🚀 Just solved today’s LeetCode challenge! 📈 This problem sharpened my skills in #DataStructures and #BitManipulation, key topics in mastering efficient code. DSA concepts like bitwise operations aren’t just cool; they’re powerful tools for optimized solutions! Ready to take on more challenges! 💪 Problem : Shortest Subarray With OR at Least K II Topics : Bit Manpulation Problem link : https://lnkd.in/gUGXNN7g Approach : Binary Search, Sliding window #LeetCodeDaily #CodeChallenge #ProblemSolving #TechJourney #Code #Logic #Development
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🚀 Day 56 of #100DaysOfCode! 🚀 Today, I tackled LeetCode problem 3133, "Minimum Array End." This one pushed my understanding of bitwise operations and iterative thinking. #Problem #Summary: Given two integers, n and x, the goal is to construct an array where each subsequent element is greater than the previous one, and the result of the bitwise AND operation across all elements equals x. My task was to return the minimum possible value of the last element in this array. #Approach: 1.) Initialize #ans with the given integer x. 2.) #Iterate from n-1 down to 0, updating #ans by performing a #bitwise #OR operation with the incremented result. 3.) The loop helps to build the array elements while #ensuring the conditions are met. #Complexity: #Time Complexity: #O(n), as we iterate n times. #Space Complexity: #O(1), since we only use a fixed amount of extra space. #Key Insight: The #bitwise OR operation with x allowed for a cumulative build-up of the array values that satisfy the problem’s requirements. This technique ensures that the resulting array fulfills the bitwise AND condition with x while producing the minimum possible last element. Onward to Day 57! 🔥 #Coding #LeetCode #BitwiseOperations #100DaysOfCode #ProblemSolving #TechJourney #DrGViswanathan Challenge
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📅 Day 13 - May 13, 2024 Today's challenge, problem #861 on LeetCode, delved into bit manipulation techniques. It's always fascinating to explore the power of bitwise operations in problem-solving! 💡 #LeetCode #MayChallenge #ProblemSolving 🚀🎉
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🚀 Day 38: LeetCode Challenge - Count Maximum OR Subsets 🚀 Problem Breakdown: Input: An array of integers. Output: Number of subsets where the bitwise OR equals the maximum achievable OR. Approach: Calculate Maximum OR: Determine the maximum OR value by iterating through the array. Recursive Backtracking: Use a backtracking function to explore all subsets, deciding to include or exclude each element. Count Valid Subsets: Check if the current subset’s OR matches the maximum OR and count it if true. Key Takeaway: This challenge showcased the power of bitwise operations and recursion in efficiently counting valid subsets. ✅ #Day38 complete! Excited to tackle more challenges ahead! 💪 #LeetCode #CodingChallenge #Day38 #50DaysOfCode #ProblemSolving #CodingJourney
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🌟 Day 12 of #100DaysofCode 🌟 Today, I worked on solving LeetCode Problem #461: Hamming Distance . The goal was to calculate the number of differing bit positions between two integers. Here's what I learned: The XOR (^) operation is incredibly powerful for comparing bits! It flags differences directly. Iterating through bits using bitwise operations (& and >>) helps in counting set bits efficiently. #100DaysOfCode #LeetCode #CodingChallenge #DynamicProgramming #CPlusPlus #ProblemSolving #VITBhopalLions #DrGVishwanathanChallenge
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🚀 Day 78 of #100DaysOfCode 🚀 Today’s challenge: Reverse Bits in a 32-bit unsigned integer 🌀 🧠 Concept: Reverse the binary representation of an integer. Move each bit from the original position to its mirror location (using bit manipulation). 💡 Key takeaway: This problem strengthened my understanding of bitwise operators. Efficient bit manipulation is a critical tool in systems and performance optimization! 📈 Result: Accepted in just 3 ms ⚡ The grind continues! Stay tuned for more! #100DaysOfCode #LeetCode #BitManipulation #ProblemSolving #C++ #Code
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🚀 Day 12 of My 100 Days of Code Challenge 🚀 Today's focus was on an interesting algorithmic problem that involves manipulating bitwise operations to achieve a specific outcome. Here's the breakdown: Problem Statement: Given two positive integers num1 and num2, find the positive integer x such that: x has the same number of set bits as num2, and The value x XOR num1 is minimized. Key steps to solving this problem: 💡 Count the number of set bits: Use Integer.bitCount to calculate the set bits in both numbers. 💡 Minimize XOR by adjusting bits: Start with num1 and adjust its bits to match the set bits of num2 while keeping the XOR value as small as possible. 💡 Iterate bit positions efficiently: Traverse the 32-bit positions to dynamically turn bits on or off. Key Takeaways: Bit Manipulation Mastery: Understanding how to toggle individual bits is crucial for problems involving XOR and set bits. Greedy Adjustment: Iterating over bit positions dynamically to minimize XOR ensures optimal performance. Constraints Consideration: The 32-bit limit allows a straightforward solution without concerns for overflow. Reflection: This problem was a fantastic exercise in understanding bitwise operations and how to optimize calculations involving binary representations. It reinforced the importance of precise control over data representations and logical operations. Looking forward to tackling more such algorithmic challenges! 🙌 #100DaysOfCode #CodingChallenge #Day12 #Java #ProblemSolving #SoftwareEngineering
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Congratulations, kabilan B! Well done on the accomplishment. We're thrilled to see it, and we're certainly rooting for you!👏👏