Various International standards such as API 610, ISO 21940, etc. specify guidelines for the dynamic balancing of the Rotor. In this article, I would like to give an example of calculation for dynamic balancing a multistage pump rotor and also the types of balancing machines. Inputs: (Rotor in the example is Rigid Rotor) Pump Rotor weight, W=200 Kg Required Balancing grade as per API 610( Table 19) =G2.5 Pump operating speed, N =2990 rpm Speed at which Rotor will be balanced =1000 rpm Calculation: V =e . w where, V = Vibration velocity, mm/s = 2.5 ( since balancing grade is G2.5) e = mass eccentricity, mm w = Angular velocity, rad/s = (2*pi*N)/60 = 313.112 Calculating mass eccentricity, e = V/w = 7.984 x 10e-3 mm = 7.984 μm Now, this eccentricity can be expressed as ( for 1 kg of total mass and 1 mm of radius), e = 7.984 gm. mm/kg Determining permissible residual unbalance, Uper Uper = e x W = 1596.8 gm.mm Being a rigid rotor, we are going for 2-plane balancing, hence calculating material to be removed from each plane. Calculating permissible residual unbalance for each tolerance plane; U per A = ( Uper x LB) / L = 781.6 gm. mm U per B= ( Uper x LA) / L = 815.2 gm. mm where, U per A is the permissible residual unbalance in bearing plane A; U per B is the permissible residual unbalance in bearing plane B; Uper is the (total) permissible residual unbalance (in the mass centre plane); LA is the distance from mass centre plane to bearing plane A ( Refer Fig.1); LB is the distance from mass centre plane to bearing plane B ( Refer Fig.1); L is the bearing span ( Refer Fig.1). For the purpose of feasibility of material removal, the correction planes have to be chosen as shown in fig.1, near the bearing/tolerance planes. Here in this example, the corrections planes I and II are set at back shroud of 2nd Impeller and 7th Impeller respectively. ( counting from A) The permissible residual unbalance tolerance value of the adjacent tolerance plane shall be allocated to the correction planes. U per I = U per A = 781.6 gm.mm U per II = U per B = 815.2 gm.mm The radius at which, the material shall be removed, R = 105 mm ( Impeller diameter assumed is 225 mm; hence material is being removed from the back shroud at the farthest point from the center.) Therefore, permissible residual imbalance mass = 7.44 gm at correction plane I and permissible residual imbalance mass = 7.76 gm at correction plane II So, at the balancing machine, the operator has to have the unbalance below these values of permissible unbalance masses at each correction plane. #pumps #mechanicalengineering #centrifugalpumps Fig. 1 Multistage Pump Rotor ( all dimensions are in mm)
Thank you for sharing balancing knowledge, further I would like know about weight removal by drilling during balancing, calculations of weght removed in gms.
Useful information... thanks for sharing.. practically on shop floor this method followed by many during dynamic balancing of rotor
Very useful well explained.
Beautiful write up... Abhijeet!!! We practically used this information on Shop floor while calculating unbalance of rotors.
Thanks for the sharing of these basics…It is of primary importance to return to fundamentals!
Senior Manager Product Portfolio Management
10moThanks for posting why the correction plan was set at the impeller 2 & 7 and not 1&8 ?