Cable cross bonding, simulation case :230KV,27Km in PSCAD

Cable cross bonding, simulation case :230KV,27Km in PSCAD

Mohaned Kamal Mohaned Kamal

Mohaned Kamal

Power System EMT Simulation Analyst | Power system Engineer | PSCAD Professional | ETAP | PSSE

Published May 3, 2024
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Cable cross-bonding essential in HV cable for longer cable

Simulation case 1: No-cross bonding, with downstream fault.

1.Cable modeled in PSCAD without cross bonding and cable sheath directly earthed in both ends with grounding resistance 10 ohm.

  • Simulation result: sheath current very high (2KA) and sheath voltage in range of 20KV under worth case, that is 3 phase to ground fault (Cable may heat up and get damage).
  • For 230KV XLPE Cable, the sheath insulation level withstands up to 100KV

Case-1: No cross bonding

Case-2: No cross bonding but SVL used (3KV rated of sheath voltage limiter) at one end and the other end directly earthed to ground.

No cross bonding with SVL

  • Result: sheath current reduced to 50% compared to case 1, and the sheath voltage limited to 6KV under fault condition.
  • Main concern is SVL will absorb high energy and will get damage.

SVL 3KV

Simulation case 3: Actual cross bonding with downstream fault.

Modeling: 27Km divided into 9 segments with segments length 3Km

Actual cross bonding model

Result: with actual cross bonding no sheath current or voltage in normal steady state.

In fault condition:

  • the sheath voltage impulse 15Kv and pretty decay
  • Sheath current impulse up to 1.5KA and pretty decay.

Case-3: Actual cross bonding

Case-4: Actual cross bonding with SVL 3KV:

  • The sheath voltage limited to 5KV and SVL energy 10KJouls.

Case-4: Actual cross bonding with SVL

Conclusion:

From simulation test bed, we can conclude that:

  • Actual cross bonding very useful in reducing sheath voltage and current.
  • With Actual cross bonding, we can use SVL rated to 3KV, 10KJ safely without damage under steady state as well as fault condition.


MIKHAIL DMITRIEV

Engineer at Voltplace.com

6mo

Mohaned, thank you for the post. What was the reason to make computer simulation? Did you do calculations using formulae? Why formulae were not enough in this 220 kV case?

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